Difference between revisions of "Part:BBa K1355004:Design"

(Design notes)
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Figure 6: A) - C) Eletrophoretic profile of the BBa_K1355003 do not digested and B) - D) digested with EcoRI + PstI.
 
Figure 6: A) - C) Eletrophoretic profile of the BBa_K1355003 do not digested and B) - D) digested with EcoRI + PstI.
  
We have a tricky molecular question! We produced the enzymatic system to isolate our biobrick, but it didn’t isolate!!! Why?!?! We thought a lot about it, and we found out!!
+
We have a tricky molecular question! We produced the enzymatic system to isolate our biobrick, but it didn’t isolate!!! Why?!?! We thought a lot about it and we found out!!
  
The answer is: the BBa_K1355004 (BBa_K1355001 + BBa_K1355000)  fragment has 3.057 base pairs, and the vector pBSK has 2.861, that’s 196 base pairs of difference! The electrophoretic profile shows only one big band in 3.000 base pairs (withparing it to the marker). That both are there, but we couldn’t separate it!  
+
The answer is: the BBa_K1355004 (BBa_K1355001 + BBa_K1355000)  fragment has 3.057 base pairs and the vector pBSK has 2.861, that’s 196 base pairs of difference! The electrophoretic profile shows only one big band in 3.000 base pairs (withparing it to the marker). That both are there, but we couldn’t separate it!  
  
 
To prove this we digested the vector PBSK with the biobrick BBa_K1355004 aiming to linearize and to isolate the fragment using EcoRI and EcoRI + PstI, respectively. The linear band should present double of band’s size digested to isolate vector from fragment. That means, the sample digested with EcoRI + PstI will show a big band in 3.000 base pairs withparing it to the marker and the sample only digested with EcoRI will show double size of that, in 6.000 base pairs! Let's check this out?!
 
To prove this we digested the vector PBSK with the biobrick BBa_K1355004 aiming to linearize and to isolate the fragment using EcoRI and EcoRI + PstI, respectively. The linear band should present double of band’s size digested to isolate vector from fragment. That means, the sample digested with EcoRI + PstI will show a big band in 3.000 base pairs withparing it to the marker and the sample only digested with EcoRI will show double size of that, in 6.000 base pairs! Let's check this out?!
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14) Restriction enzyme digestion of BBa_K1355001 + BBa_K1355000 (BBa_K1355004) only with EcoRI and with EcoRI + PstI;
 
14) Restriction enzyme digestion of BBa_K1355001 + BBa_K1355000 (BBa_K1355004) only with EcoRI and with EcoRI + PstI;
  
13) Checking the electrophoretic profile of the digested sample to answer the molecular question:
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15) Checking the electrophoretic profile of the digested sample to answer the molecular question:
  
 
[[File:04DigstECOECOPSTi.jpg]]
 
[[File:04DigstECOECOPSTi.jpg]]
  
Figure 6: A) BBa_K1355004 in pBSK do not digested; B) digested only with EcoRI and C) digested with EcoRI + PstI
+
Figure 7: A) BBa_K1355004 in pBSK do not digested; B) digested only with EcoRI and C) digested with EcoRI + PstI
 
+
  
 +
B) One band in 6.000 base pairs withparing it to the marker, the BioBrick only linearize by EcoRI. C) Two bands in 3.000 base pairs withparing it to the marker! We proved our hypothesis! How are we going to separate our biobrick BBa_K1355004 from the pBSK vector for cloning it in PSB1C3, considering that both of the vector and the fragment has around 3.000 base pairs! We solved it and developed the following strategy:
  
 +
16)
  
  
  
 
===References===
 
===References===

Revision as of 20:57, 12 October 2014

Design notes

For this genetic construction, we followed these summarized steps in the following image:

ESQUEMA.jpg

1) Transformation of DH5-alpha with the Biobrick - Strong RBS + merA (mercuric ion reductase)+ terminator (BBa_ B0015) - BBa_K1355000 and with the Essential Biobrick - Regulation and transport of mercury - BBa_K1355001 that contains a bidiretional promotor regulated by the MerR protein.

2) Extraction and quantification of plasmid DNA of the BBa_K1355000 and BBa_K1355001;

3) Verifying the electrophoretic profile of the extracted plasmid DNA;

DNApRTPMERA.jpg

Figure 1: Eletrophoretic profile of the BBa_K1355001 and of BBa_K1355000 plasmid DNA.

4) Restriction enzyme digestion of the BBa_K1355001 with SpeI and EcoRI and of BBa_K1355000 with EcoRI and XbaI aiming to isolate the biobrick fragment and linearize the vector, respectively;

5) Checking the electrophoretic profile of digested samples;

DigstRTPMERA.jpg

Figure 2: (1) Electrophoretic profile of BBa_K1355000 do not digested and (2) digested with XbaI and EcoRI; (3) Eletrophoretic profile of the BBa_K1355001 do not digested and (4) digested with EcoRI and XbaI.

6) Purification from agarose gel of the fragment (Biobrick BBa_K1355001) and the linearized vector (BBa_K1355000);

7) Checking the electrophoretic profile of purified samples;

PuriRTPMerA.jpg

Figure 3: (1) Eletrophoretic profile of BBa_K1355000 (linearized vector) purified; B) Eletrophoretic profile of BBa_K1355001 (fragment) purified.

8) Ligation of the linearized vector with fragment using T4 DNA ligase;

9) Transformation of the ligation in DH5-alpha;

Bioremediaaator.jpg

Figure 4: Mercury Bacter Hg bioremediator (DH5-alpha transformed with BBa_K1355004)

10) Extraction of plasmid DNA with our bioremediator constrution from DH5-alpha transformed;

11) Check the electrophoretic profile to see results of samples linked;

Figure5RTPMERA.jpg

Figure 5: Electrophoretic profile of BBa_K1355004 plasmid DNA in pBSK.


12) Restriction enzyme digestion of BBa_K1355001 + BBa_K1355000 (BBa_K1355004) with EcoRI + PstI aiming to analyze the fragment size to be isolated;

13) Checking the electrophoretic profile of the digested sample to obtain results showing that the isolated fragment is the junction of BBa_K1355001 + BBa_K1355000 in pBSK;


PBSKdigsted.jpg


Figure 6: A) - C) Eletrophoretic profile of the BBa_K1355003 do not digested and B) - D) digested with EcoRI + PstI.

We have a tricky molecular question! We produced the enzymatic system to isolate our biobrick, but it didn’t isolate!!! Why?!?! We thought a lot about it and we found out!!

The answer is: the BBa_K1355004 (BBa_K1355001 + BBa_K1355000) fragment has 3.057 base pairs and the vector pBSK has 2.861, that’s 196 base pairs of difference! The electrophoretic profile shows only one big band in 3.000 base pairs (withparing it to the marker). That both are there, but we couldn’t separate it!

To prove this we digested the vector PBSK with the biobrick BBa_K1355004 aiming to linearize and to isolate the fragment using EcoRI and EcoRI + PstI, respectively. The linear band should present double of band’s size digested to isolate vector from fragment. That means, the sample digested with EcoRI + PstI will show a big band in 3.000 base pairs withparing it to the marker and the sample only digested with EcoRI will show double size of that, in 6.000 base pairs! Let's check this out?!

14) Restriction enzyme digestion of BBa_K1355001 + BBa_K1355000 (BBa_K1355004) only with EcoRI and with EcoRI + PstI;

15) Checking the electrophoretic profile of the digested sample to answer the molecular question:

04DigstECOECOPSTi.jpg

Figure 7: A) BBa_K1355004 in pBSK do not digested; B) digested only with EcoRI and C) digested with EcoRI + PstI

B) One band in 6.000 base pairs withparing it to the marker, the BioBrick only linearize by EcoRI. C) Two bands in 3.000 base pairs withparing it to the marker! We proved our hypothesis! How are we going to separate our biobrick BBa_K1355004 from the pBSK vector for cloning it in PSB1C3, considering that both of the vector and the fragment has around 3.000 base pairs! We solved it and developed the following strategy:

16)


References